document.write( "Question 673680: log х 0.125 =-3 \n" ); document.write( "
Algebra.Com's Answer #418768 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "Assume You meant 0.125
\n" ); document.write( "\"log%28x%2C.125%29+=+-3\"
\n" ); document.write( "x^(-3) = .125
\n" ); document.write( "0r 1/x^3 = .125
\n" ); document.write( "x^3 = 1/.125 = 8,
\n" ); document.write( " x^3 = 8
\n" ); document.write( " x = 2 \n" ); document.write( "
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