document.write( "Question 673683: log(x+12)=2 \n" ); document.write( "

Algebra.Com's Answer #418766 by MathLover1(20850) $\"\"$ $\"About$

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When:\r
\n" ); document.write( "\n" ); document.write( " $\"b+%5Ey+=+x\"$ \r
\n" ); document.write( "\n" ); document.write( "Then the base $\"b\"$ logarithm of a number $\"x\"$ :\r
\n" ); document.write( "\n" ); document.write( " $\"log%28b%28+x+%29%29=+y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+log%28%28x%2B12%29%29=2+\"$ ...... $\"b=e\"$ , $\"y=2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"e%5E2=x%2B12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"e%5E2-12=x\"$ \n" ); document.write( "

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