document.write( "Question 673595: The stopping distance (D) of a vehicle varies directly as the square of its velocity (V). If a vehicle traveling 40 mph requires 100 feet to come to a stop, find the stopping distance of a vehicle traveling 60 mph.\r
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document.write( "I started with y=kx for \"varies directly\" and did not know where to go from there. Also, I am not sure that I am using the correct method in considering this problem. The \"square of its velocity\" is throwing me off. \n" );
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Algebra.Com's Answer #418748 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The stopping distance (D) of a vehicle varies directly as the square of its velocity (V). If a vehicle traveling 40 mph requires 100 feet to come to a stop, find the stopping distance of a vehicle traveling 60 mph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the stopping distance varies directly as the square of its velocity (V), then:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "100 = 1,600k\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "k = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D, or stopping distance = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |