document.write( "Question 673595: The stopping distance (D) of a vehicle varies directly as the square of its velocity (V). If a vehicle traveling 40 mph requires 100 feet to come to a stop, find the stopping distance of a vehicle traveling 60 mph.\r
\n" ); document.write( "\n" ); document.write( "I started with y=kx for \"varies directly\" and did not know where to go from there. Also, I am not sure that I am using the correct method in considering this problem. The \"square of its velocity\" is throwing me off.
\n" ); document.write( "

Algebra.Com's Answer #418748 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The stopping distance (D) of a vehicle varies directly as the square of its velocity (V). If a vehicle traveling 40 mph requires 100 feet to come to a stop, find the stopping distance of a vehicle traveling 60 mph.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the stopping distance varies directly as the square of its velocity (V), then:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D+=+kV%5E2\", with k being the constant of variation \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"100+=+k40%5E2\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "100 = 1,600k\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "k = \"100%2F1600\", or \"1%2F16\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D+=+kV%5E2\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\"D+=+%281%2F16%29+%2A+60%5E2\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D+=+%281%2F16%29+%2A+3600\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "D, or stopping distance = \"highlight_green%28225%29\" ft\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
\n" ); document.write( "
\n" );