document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=673595>Question 673595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The stopping distance (D) of a vehicle varies directly as the square of its velocity (V).  If a vehicle traveling 40 mph requires 100 feet to come to a stop, find the stopping distance of a vehicle traveling 60 mph.\r<BR>\n" );
document.write( "\n" );
document.write( "I started with y=kx for \"varies directly\" and did not know where to go from there.  Also, I am not sure that I am using the correct method in considering this problem.  The \"square of its velocity\" is throwing me off.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418746 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> stopping distance (D) of a vehicle varies directly as the square of its velocity (V)<BR>\n" );
document.write( "so D/V2=const<BR>\n" );
document.write( "or 100/(40)2=D/(60)2<BR>\n" );
document.write( "or D=100*(60/40)2=150 feet<BR>\n" );
document.write( "ans </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );