document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=673624>Question 673624</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jason invested $12,000 in two funds. One of the funds returned 6% interest, and the other returned 8% interest after one year. If the total interest for the year was $880, how much did he invest in each fund? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418736 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let investment in one of the fund is $x returned 6% interest, and investment in the other the fund is $(12000-x) returned 8% interest after one year. <BR>\n" );
document.write( "so the total interest =6*x/100+8*(12000-x)/100=880 (as per question)<BR>\n" );
document.write( "or 6x+8(12000-x)=88000<BR>\n" );
document.write( "or -2x=88000-96000=-8000<BR>\n" );
document.write( "or x=4000\r<BR>\n" );
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document.write( "so 1st investment is 4000 at 6% & other is 8000 at 8% </SPAN>\n" );
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