document.write( "Question 673192: find the domain of f(x) = sqrt(16-x^2) \n" ); document.write( "

Algebra.Com's Answer #418734 by ReadingBoosters(3246) $\"\"$ $\"About$

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f(x) = $\"sqrt%2816-x%5E2%29\"$
\n" ); document.write( "Cannot have a negative under square root, so
\n" ); document.write( " $\"0%3C=16-x%5E2\"$
\n" ); document.write( "Rearrange
\n" ); document.write( " $\"x%5E2+%3C=+16\"$
\n" ); document.write( " $\"sqrt%28x%5E2%29\"$ <= +/- $\"sqrt%2816%29\"$
\n" ); document.write( " $\"-4+%3C=+x+%3C=+4\"$
\n" ); document.write( "...
\n" ); document.write( "Domain is all x between -4 and 4
\n" ); document.write( "[-4, 4]
\n" ); document.write( "...
\n" ); document.write( " $\"graph%28300%2C200%2C-5%2C5%2C-2%2C10%2Csqrt%2816-x%5E2%29%29\"$
\n" ); document.write( ".....................
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\n" ); document.write( "-Reading Boosters
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