document.write( "Question 60914: I can only solve part of this equation and then I get stuck. Can someone show me the next steps I need to take and explain how they are done? I have done the equation as far as I can:\r
\n" ); document.write( "\n" ); document.write( "SQRT(2X-1)+SQRT(X-4)= 4 <----original equation\r
\n" ); document.write( "\n" ); document.write( "SQRT(2X-1)=4-SQRT(X-4)
\n" ); document.write( "(SQRT<2X-1>)^2 = (4-SQRT)^2
\n" ); document.write( "2X-1 = (4-SQRT)(4-SQRT) <------I am lost as to how to solve finish this side of the equation.\r
\n" ); document.write( "\n" ); document.write( "Thanks!
\n" ); document.write( "

Algebra.Com's Answer #41869 by joyofmath(189)\"\" \"About 
You can put this solution on YOUR website!
The equation to solve is \"sqrt%282x-1%29%2Bsqrt%28x-4%29=4\".\r
\n" ); document.write( "\n" ); document.write( "This is a quadratic equation in disguise!
\n" ); document.write( "The trick to solving these is to get all the square root stuff onto one side of the equation then square both sides. Then, you're left with a quadratic equation to solve:\r
\n" ); document.write( "\n" ); document.write( "Square both sides of the equation to solve:
\n" ); document.write( "\"%28sqrt%282x-1%29%29%5E2+%2B+sqrt%28x-4%29%5E2+=+4%5E2+=+16\"\r
\n" ); document.write( "\n" ); document.write( "This expands to:
\n" ); document.write( "\"%282x-1%29%2B%28x-4%29%2B2sqrt%28%282x-1%29%28x-4%29%29+=+16\"\r
\n" ); document.write( "\n" ); document.write( "Collect like terms:
\n" ); document.write( "\"3x-5%2B2sqrt%28%282x-1%29%28x-4%29%29+=+16\"\r
\n" ); document.write( "\n" ); document.write( "Subtract 16 from both sides:
\n" ); document.write( "\"3x-21%2B2sqrt%28%282x-1%29%28x-4%29%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Subtract \"2sqrt%28%282x-1%29%28x-4%29%29\" from both sides:
\n" ); document.write( "\"3x-21+=+-+2sqrt%28%282x-1%29%28x-4%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Now, square both sides:
\n" ); document.write( "\"%283x-21%29%5E2+=+%28-2sqrt%28%282x-1%29%28x-4%29%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Multiply things out:
\n" ); document.write( "\"9x%5E2-126x%2B441+=+4%282x-1%29%28x-4%29\"\r
\n" ); document.write( "\n" ); document.write( "Or \"9x%5E2-126x%2B441+=+4%282x%5E2-9x%2B4%29+=+8x%5E2-36x%2B16\"\r
\n" ); document.write( "\n" ); document.write( "Subtract \"8x%5E2\" from both sides:
\n" ); document.write( "\"x%5E2-126x%2B441=-36x%2B16\"\r
\n" ); document.write( "\n" ); document.write( "Subtract 16 from both sides:
\n" ); document.write( "\"x%5E2-126x%2B425=-36x\"\r
\n" ); document.write( "\n" ); document.write( "Add 36x to both sides:
\n" ); document.write( "\"x%5E2-90x%2B425=0\"\r
\n" ); document.write( "\n" ); document.write( "This is a quadratic equation that you can solve with the quadratic formula or by factoring the equation if you can see the factors:\r
\n" ); document.write( "\n" ); document.write( "The equation factors into \"%28x-85%29%28x-5%29\"
\n" ); document.write( "The roots of the equation are 85 and 5\r
\n" ); document.write( "\n" ); document.write( "If you plug 85 into your original equation it doesn't work but 5 does so \"5\" is your answer.
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