document.write( "Question 60915This question is from textbook
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document.write( ": The cost of producing a number of items x is given by C = mx + b, in which b is the fixed cost and m is the variable cost (the cost of producing one more item).
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document.write( "(a) If the fixed cost is $40 and the variable cost is $10, write the cost equation.
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document.write( "(b) Graph the cost equation.
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document.write( "(c) The revenue generated from the sale of x items is given by R = 50x. Graph the revenue equation on the same set of axes as the cost equation.
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document.write( "(d) How many items must be produced for the revenue to equal the cost (the break-even point)? \n" );
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Algebra.Com's Answer #41866 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! The cost of producing a number of items x is given by C = mx + b, in which b is the fixed cost and m is the variable cost (the cost of producing one more item). \n" ); document.write( "(a) If the fixed cost is $40 and the variable cost is $10, write the cost equation. \n" ); document.write( "b=40, m=10 \n" ); document.write( " \n" ); document.write( "(b) Graph the cost equation. \n" ); document.write( " \n" ); document.write( "(c) The revenue generated from the sale of x items is given by R = 50x. Graph the revenue equation on the same set of axes as the cost equation. \n" ); document.write( " \n" ); document.write( "(d) How many items must be produced for the revenue to equal the cost (the break-even point)? The lines intersect at (1,50), therefore the number of items that must be produced to break even is x=1. \n" ); document.write( "You could have found this algebraically by letting C=R \n" ); document.write( "10x+40=50x \n" ); document.write( "10x-10x+40=50x-10x \n" ); document.write( "40=40x \n" ); document.write( "40/40=40x/40 \n" ); document.write( "1=x \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |