document.write( "Question 673332: Find three consecutive integers such that twice the greatest integer is 2 less than 3 times the least integer. Please help me solve this \n" ); document.write( "

Algebra.Com's Answer #418608 by KMST(5328) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the three consecutive integers be $\"n\"$ , $\"n%2B1\"$ , and $\"n%2B2\"$ .
\n" ); document.write( "The greatest integer is $\"n%2B2\"$ .
\n" ); document.write( "Twice the greatest integer is $\"2%28n%2B2%29\"$ .
\n" ); document.write( "The least integer is $\"n\"$ .
\n" ); document.write( "Three times the least integer is $\"3n\"$ .
\n" ); document.write( "Then, 2 less than 3 times the least integer is $\"3n-2\"$
\n" ); document.write( "Twice the greatest integer is 2 less than 3 times the least integer
\n" ); document.write( "translates as $\"2%28n%2B2%29=3n-2\"$
\n" ); document.write( " $\"2%28n%2B2%29=3n-2\"$ --> $\"2n%2B4=3n-2\"$ --> $\"2n%2B4-2n=3n-2-2n\"$ --> $\"4=n-2\"$ --> $\"4%2B2=n-2%2B2\"$ --> $\"6=n\"$ or $\"highlight%28n=6%29\"$
\n" ); document.write( "So the three consecutive integers are $\"highlight%286%29\"$ , $\"highlight%287%29\"$ , and $\"highlight%288%29\"$ . \n" ); document.write( "

\n" );