document.write( "Question 673310: A does 4/5 of a work in 20 days.He then calls in B and together finish the remaining work in 3 days. how long B would take to do the whole work?
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Algebra.Com's Answer #418588 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "A does 4/5 of a work in 20 days. \"4%2F5+=+20%2F25+\" 1/25 per day
\n" ); document.write( " In 3 days then 3/25 of work: 1/5 - 3/25 = 2/25 left for B to do in 3 days
\n" ); document.write( " \"3%2A%282%2F75%29+=+2%2F25\"
\n" ); document.write( " B can do 2/75 of the total work in one day. \"37.5%282%2F75%29+=+1\"
\n" ); document.write( " 37 1/2 days to do the whole work \n" ); document.write( "
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