document.write( "Question 60904: If a line through the center of a circle is perpendicular to a chord, then the line also bisects the chord.\r
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document.write( "I have some work done with a drawing on sketchpad, but I am not sure where to even start with writing my proof. They make no sense to me since I have not had a good teacher to teach me proofs. Thank you \n" );
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Algebra.Com's Answer #41855 by asha(30)![]() ![]() ![]() You can put this solution on YOUR website! let AB be a chord in the circle \n" ); document.write( "let line XY intersect the chord at P. \n" ); document.write( "let O be the centre of the circle. \n" ); document.write( "OP is perpendicular to AB. \n" ); document.write( "Join OA and OB. \n" ); document.write( "you have 2 right angled triangles OAP and OBP. \n" ); document.write( "Considering the two triangles, we have \n" ); document.write( "OA = OB radii of the circle and the hypotenuse of the right triangles. \n" ); document.write( "OP is common to the two triangles. \n" ); document.write( "angle OPA = angle OPB =90 degrees. \n" ); document.write( "therefore the two triangles are congruent.(right angle, hypotenuse and side) \n" ); document.write( "hence AP =PB (corresponding parts of congruent triangles are equal) \n" ); document.write( "the line OP bisects chord AB. \n" ); document.write( " |