document.write( "Question 673245: Find the length of the shorter leg of a right triangle if the longer leg is 12 feet more than the shorter leg and the hypotenuse is 12 feet less than twice the shorter leg.\r
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Algebra.Com's Answer #418547 by stanbon(75887)\"\" \"About 
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Find the length of the shorter leg of a right triangle if the longer leg is 12 feet more than the shorter leg and the hypotenuse is 12 feet less than twice the shorter leg.
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\n" ); document.write( "Let the shorter leg be \"x\".
\n" ); document.write( "Other leg: \"x+12\"
\n" ); document.write( "Hypotenuse: \"2x-12\"
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\n" ); document.write( "Equation:
\n" ); document.write( "(2x-12)^2 = x^2 + (x+12)^2
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\n" ); document.write( "4x^2 - 48x + 144 = 2x^2 + 24x + 144
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\n" ); document.write( "2x^2 - 72x = 0
\n" ); document.write( "2x(x-36) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 36 (shorter leg)
\n" ); document.write( "x+12 = 48 (longer leg)
\n" ); document.write( "2x-12 = 60 (hypotenuse)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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