document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=673217>Question 673217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pleas Solve<BR>\n" );
document.write( "4/(x+3) + 3/(2x-1) =1\r<BR>\n" );
document.write( "\n" );
document.write( "4(2x-1)/(x+3)(2x-1) + 3(x+3)/(x+3)(2x-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418522 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4/(x+3) + 3/(2x-1) =1<BR>\n" );
document.write( "Multiply thru by (x+3)(2x-1) to get:<BR>\n" );
document.write( "4(2x-1) + 3(x+3) = (x+3)(2x-1)<BR>\n" );
document.write( "8x-4+3x+9 = 2x^2+5x-3<BR>\n" );
document.write( "2x^2 -6x -8 = 0<BR>\n" );
document.write( "x^2 -3x -4 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(x-4)(x+1) = 0<BR>\n" );
document.write( "x = 4 or x = -1<BR>\n" );
document.write( "=============================<BR>\n" );
document.write( " <BR>\n" );
document.write( "4(2x-1)/(x+3)(2x-1) + 3(x+3)/(x+3)(2x-1)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "The denominators are the same, so just add the numerators<BR>\n" );
document.write( "over the common denominator.<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= [8x-4+3x+9]/[(x+3)(2x-1)]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= [12x+5] / [(x+3)(2x-1)]<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=================== </SPAN>\n" );
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