document.write( "Question 673208: 1. x+4y=14
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document.write( " 2x-y=1 solve using substitution method \n" );
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Algebra.Com's Answer #418520 by rm29924(97)![]() ![]() You can put this solution on YOUR website! take the first equation and get x by itself \n" ); document.write( "x+4y = 14 \n" ); document.write( "to get x by itself subtract 4y from both sides \n" ); document.write( "x+4y = 14 \n" ); document.write( " -4y -4y\r \n" ); document.write( "\n" ); document.write( "x= 14-4y\r \n" ); document.write( "\n" ); document.write( "now substitue this value for x in the second equation \n" ); document.write( "2x-y=1 \n" ); document.write( "2(14-4y)-y=1 \n" ); document.write( "multiply everything in the parenthesis by 2 \n" ); document.write( "2(14) 2(-4y) \n" ); document.write( "28-8y-y=1 \n" ); document.write( "28-9y=1 \n" ); document.write( "add 9y to both sides \n" ); document.write( "28=1+9y \n" ); document.write( "subtract 1 from both sides \n" ); document.write( "27=9y \n" ); document.write( "divide both sides by 9 \n" ); document.write( "3=y\r \n" ); document.write( "\n" ); document.write( "now substitue the value for y in the first equation to get x \n" ); document.write( "x+4y=14 \n" ); document.write( "x+4(3)=14 \n" ); document.write( "x+12=14 \n" ); document.write( "subtract 12 from both sides \n" ); document.write( "x=2\r \n" ); document.write( "\n" ); document.write( "answer: x=2 y=3\r \n" ); document.write( "\n" ); document.write( "check work: \n" ); document.write( "x+4y=14 \n" ); document.write( "2+4(3)=14 \n" ); document.write( "2+12=14 \n" ); document.write( "14+14\r \n" ); document.write( "\n" ); document.write( "2x-y=1 \n" ); document.write( "2(2)-3=1 \n" ); document.write( "4-3=1 \n" ); document.write( "1=1 \n" ); document.write( " |