document.write( "Question 673067: How do I solve the equation 4^2X=64? The teacher gave us the answer, 3/2, but I don't know the steps to get to that answer. \n" ); document.write( "
Algebra.Com's Answer #418469 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"4%5E%282x%29=64\"\r
\n" ); document.write( "\n" ); document.write( "\"4%5E%282x%29=4%5E3\"........if base same, exponents are same too; so, we have\r
\n" ); document.write( "\n" ); document.write( "\"2x=3\"\r
\n" ); document.write( "\n" ); document.write( "\"x=3%2F2\"
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