document.write( "Question 60884This question is from textbook Mathematics 11
\n" ); document.write( ": A survey crew took a trip up the river and back in 10 h. Going upstream they paddled at 4 km/h, but downstream they travelled at 12 km/h. How far upstream did the crew go? \n" ); document.write( "
Algebra.Com's Answer #41845 by uma(370)\"\" \"About 
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Let the distance travelled upstream = x km
\n" ); document.write( "Speed while going upstream = 4 km/h\r
\n" ); document.write( "\n" ); document.write( "So time taken = distance/speed
\n" ); document.write( " = (x/4)h\r
\n" ); document.write( "\n" ); document.write( "Speed while travelling downstream = 12 km/h\r
\n" ); document.write( "\n" ); document.write( "So time taken = distance/speed
\n" ); document.write( " = (x/12)h [distance upstream = distance downstream]\r
\n" ); document.write( "\n" ); document.write( "Total time taken = 12 h\r
\n" ); document.write( "\n" ); document.write( "==> x/4 + x/12 = 4\r
\n" ); document.write( "\n" ); document.write( "The LCD for the left side = 12
\n" ); document.write( "==> (3x + x)/12 = 4
\n" ); document.write( "==> 4x/12 = 4
\n" ); document.write( "multiplying both the sides by 12 we get..
\n" ); document.write( "==> 4x = 48
\n" ); document.write( "==> 4x/4 = 48/4
\n" ); document.write( "==> x = 12\r
\n" ); document.write( "\n" ); document.write( "So the distance upstream = 12 km\r
\n" ); document.write( "\n" ); document.write( "Good Luck!!!\r
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