document.write( "Question 672987: The braking distance of a sample of Ford F-150's are normally distributed. On a dry surface, the mean braking distance was 158 feet with a standard deviation of 7.23 ft. What is the longest braking distance on a dry surface one of these F-150 trucks could have an still be in the best 1%? \n" ); document.write( "
Algebra.Com's Answer #418428 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The braking distance of a sample of Ford F-150's are normally distributed. On a dry surface, the mean braking distance was 158 feet with a standard deviation of 7.23 ft. What is the longest braking distance on a dry surface one of these F-150 trucks could have and still be in the best 1%? \n" ); document.write( "----- \n" ); document.write( "I'm guessing the best 1% means shorter braking distances. \n" ); document.write( "I may be wrong about what is \"best\". \n" ); document.write( "------ \n" ); document.write( "The z-value with a left-tail of 1% is -2.4363 \n" ); document.write( "--- \n" ); document.write( "The corresponding distance value is x = z*s+u \n" ); document.write( "x = -2.4363*7.23+158 \n" ); document.write( "--- \n" ); document.write( "x = 141.18 feet \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |