document.write( "Question 672940: The area is 4700 square feet. The length is twice the width minus six feet. I need help setting up the problem and solving it. \n" ); document.write( "

Algebra.Com's Answer #418409 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let The width = $\"+w+\"$ ft
\n" ); document.write( "You are given that the length = $\"+2w+-+6+\"$ ft
\n" ); document.write( "Let area = $\"+A+\"$
\n" ); document.write( " $\"+A+\"$ = length x width
\n" ); document.write( " $\"+A+=+w%2A%28+2w+-+6+%29+\"$ ft2
\n" ); document.write( "You are given that $\"+A+=+4700+\"$ ft2
\n" ); document.write( " $\"+4700+=+w%2A%28+2w+-+6+%29+\"$
\n" ); document.write( " $\"+4700+=+2w%5E2+-+6w+\"$
\n" ); document.write( " $\"+2w%5E2+-+6w+-+4700+=+0+\"$
\n" ); document.write( "Divide both sides by $\"+2+\"$
\n" ); document.write( "

\n" ); document.write( " $\"+a+=+1+\"$
\n" ); document.write( " $\"+b+=+-3+\"$
\n" ); document.write( " $\"+c+=+-2350+\"$
\n" ); document.write( " $\"+w+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2+-+4%2A1%2A%28-2350%29+%29%29+%2F+%282%2A1%29+\"$
\n" ); document.write( " $\"+w+=+%28+3+%2B-+sqrt%28+9+%2B+9400+%29%29+%2F+2+\"$
\n" ); document.write( " $\"+w+=+%28+3+%2B-+sqrt%28+9409+%29%29+%2F+2+\"$
\n" ); document.write( " $\"+w+=+%28+3+%2B+97+%29+%2F+2+\"$ ( ignore the negative square root of 9409 )
\n" ); document.write( " $\"+w+=+100%2F2+\"$
\n" ); document.write( " $\"+w+=+50+\"$
\n" ); document.write( " $\"+2w+-+6+=+2%2A50+-+6+\"$
\n" ); document.write( " $\"+2w+-+6+=+94+\"$
\n" ); document.write( "The width is 50 ft and
\n" ); document.write( "the length is 94 ft
\n" ); document.write( "-------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+A+=+50%2A94+\"$
\n" ); document.write( " $\"+A+=+4700+\"$
\n" ); document.write( "OK \n" ); document.write( "

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