document.write( "Question 672872: What are the zeros of this function:
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Algebra.Com's Answer #418362 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=%28x%2B6%29%5E2%2B2\"...set it equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2%2B12x%2B36%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B12x%2B38=0\"..use quadratic formula to find zeros\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+12%5E2-4%2A1%2A38+%29%29%2F%282%2A1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+144-152%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+-8%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28%28-1%294%2A2%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B-+2i%2Asqrt%282%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "complex solutions:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+%2B2i%2Asqrt%282%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-12%2F2+%2B2i%2Asqrt%282%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+-6+%2Bi%2Asqrt%282%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-12+-2i%2Asqrt%282%29%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-12%2F2+-2i%2Asqrt%282%29%2F2+\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+-6+-i%2Asqrt%282%29%29+\"\r
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