document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=672865>Question 672865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of one angle of a triangle is 26 degrees less than twice the measure of another angle. the measure of the third angle is 35. find the measure of the other two angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418349 by </B><A HREF=/tutors/aboutme.mpl?userid=rm29924><B>rm29924(97)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rm29924><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rm29924><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of angles in a triangle = 180 degrees\r<BR>\n" );
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document.write( "one angle is 35<BR>\n" );
document.write( "let x=another angle<BR>\n" );
document.write( "the third angle is 2x-26\r<BR>\n" );
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document.write( "35+x+2x-26=180<BR>\n" );
document.write( "combine like terms<BR>\n" );
document.write( "9+3x=180 <BR>\n" );
document.write( "subtract 9 from both sides<BR>\n" );
document.write( "3x=171<BR>\n" );
document.write( "divide both sides by 3 to get the value of x<BR>\n" );
document.write( "x=57\r<BR>\n" );
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document.write( "2(57)-26=88\r<BR>\n" );
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document.write( "the other two angles are 57 degrees and 88 degrees\r<BR>\n" );
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document.write( "check work<BR>\n" );
document.write( "35+57+2(57)-26=180<BR>\n" );
document.write( "35+57+114-26=180<BR>\n" );
document.write( "180=180\r<BR>\n" );
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document.write( " </SPAN>\n" );
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