document.write( "Question 672824: A and B do a work together in five days If A do the work with double speed and B with half the speed then they do the work in 4 days together find A alone do the work in how much time. \n" ); document.write( "
Algebra.Com's Answer #418335 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A and B do a work together in five days \n" ); document.write( " If A do the work with double speed and \n" ); document.write( " B with half the speed then they do the work in 4 days together \n" ); document.write( " find A alone do the work in how much time. \n" ); document.write( ": \n" ); document.write( "let a = A's time alone \n" ); document.write( "let b = B's time alone \n" ); document.write( "then \n" ); document.write( ".5a = A's time when working twice as fast \n" ); document.write( "and \n" ); document.write( "2b = B's time when working half as fast \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "Write a shared work equation for each scenario \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "get rid of the denominators, mult by ab \n" ); document.write( "5b + 5a = ab \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "multiply by 2ab to get rid of the denominators \n" ); document.write( "4b(4) + 4a = 2ab \n" ); document.write( "16b + 4a = 2ab \n" ); document.write( ": \n" ); document.write( "Use elimination here, mult the 1st equation by 4, mult the 2nd eq by 5 \n" ); document.write( "then subtract the 1st from the 2nd \n" ); document.write( "80b + 20a = 10ab \n" ); document.write( "20b + 20a = 4ab \n" ); document.write( "------------------subtraction eliminates a \n" ); document.write( "60b + 0 = 6ab \n" ); document.write( "divide both sides by b \n" ); document.write( "60 = 6a \n" ); document.write( "a = 60/6 \n" ); document.write( "a = 10 days working alone \n" ); document.write( " |