document.write( "Question 672834: hello:)im not all that good at math its a subsitution problem and i need help! please.\r
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document.write( "y=x-1
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document.write( "3x+4y=17 \n" );
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Algebra.Com's Answer #418331 by Alan3354(69443) You can put this solution on YOUR website! y=x-1 \n" ); document.write( "3x+4y=17 \n" ); document.write( "----------- \n" ); document.write( "y is solved for in the 1st eqn, so sub for y in the 2nd. \n" ); document.write( "----- \n" ); document.write( "3x+4y=17 \n" ); document.write( "3x + 4(x-1) = 17 \n" ); document.write( "3x + 4x-4 = 17 \n" ); document.write( "7x = 21 \n" ); document.write( "x = 3 \n" ); document.write( "----- \n" ); document.write( "y = x-1 \n" ); document.write( "y = 2 \n" ); document.write( "------- \n" ); document.write( "Nothing to it. \n" ); document.write( " \n" ); document.write( " |