document.write( "Question 672800: find four consecutive odd integers such that twice the sum of the first two is 56 greater than the sum of the third and the fourth.\r
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Algebra.Com's Answer #418316 by stanbon(75887)\"\" \"About 
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find four consecutive odd integers such that twice the sum of the first two is 56 greater than the sum of the third and the fourth.
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\n" ); document.write( "1st: 2x-3
\n" ); document.write( "2nd: 2x-1
\n" ); document.write( "3rd: 2x+1
\n" ); document.write( "4th: 2x+3
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\n" ); document.write( "Equation:
\n" ); document.write( "2(4x-4) = (4x+4)+56
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\n" ); document.write( "8x-8 = 4x + 60
\n" ); document.write( "4x = 68
\n" ); document.write( "x = 17
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\n" ); document.write( "1st: 2x-3 = 31
\n" ); document.write( "2nd: 33
\n" ); document.write( "3rd: 35
\n" ); document.write( "4th: 37
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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