document.write( "Question 671398: how to solve logx 49/64= -2\r
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document.write( "solve for x:
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document.write( "logx 2=1/3\r
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document.write( "simplify log2 2^2=log5 5^2-log4 4^2\r
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document.write( "find antilog base of 9 power of 3\r
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document.write( "write as a single logarithim: 3 log(y^2-9)-4 log x-4 log(y+3)+log(3x+xy) \n" );
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Algebra.Com's Answer #418284 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! how to solve logx 49/64= -2 \n" ); document.write( "x^-2=49/64 \n" ); document.write( "1/x^2=49/64 \n" ); document.write( "take sqrt of both sides \n" ); document.write( "1/x=7/8 \n" ); document.write( "x=8/7 \n" ); document.write( ".. \n" ); document.write( "solve for x: \n" ); document.write( "logx 2=1/3 \n" ); document.write( "x^1/3=2 \n" ); document.write( "cube both sides \n" ); document.write( "x=2^3 \n" ); document.write( "x=8 \n" ); document.write( ".. \n" ); document.write( "simplify log2 2^2=log5 5^2-log4 4^2 \n" ); document.write( "log of base raised to a power=power \n" ); document.write( "2=2-2 \n" ); document.write( "2≠0 (no solution) \n" ); document.write( ".. \n" ); document.write( "find antilog base of 9 power of 3 \n" ); document.write( "9^3=729 \n" ); document.write( "base(9) raised to log of number(3)=number (729) \n" ); document.write( ".. \n" ); document.write( "write as a single logarithim: \n" ); document.write( "3 log(y^2-9)-4 log x-4 log(y+3)+log(3x+xy) \n" ); document.write( "log[(y^2-9)^3*(3x+xy)/(x^4)*(y+3)^4] \n" ); document.write( " |