document.write( "Question 672717: 1) Use the method of substitution to solve the system of linear equations\r
\n" ); document.write( "\n" ); document.write( "3x-y=5
\n" ); document.write( "7x-2y=15\r
\n" ); document.write( "\n" ); document.write( "2) use the method of substitution to solve lineear equations\r
\n" ); document.write( "\n" ); document.write( "3a=2-b
\n" ); document.write( "3a=7-b\r
\n" ); document.write( "\n" ); document.write( "3)Solve the system of linear equations
\n" ); document.write( "3x-y=0
\n" ); document.write( "2x-y=1
\n" ); document.write( "

Algebra.Com's Answer #418274 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "1.
\n" ); document.write( "\"3x-y=5\"
\n" ); document.write( "\"7x-2y=15\"\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a linear system of equations by subsitution

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-1%2Ay=5\"
\n" ); document.write( " \"7%2Ax-2%2Ay=15\"
\n" ); document.write( "
\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
\n" ); document.write( "
\n" ); document.write( " Solve for y for the first equation
\n" ); document.write( "
\n" ); document.write( " \"-1%2Ay=5-3%2Ax\"Subtract \"3%2Ax\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"y=%285-3%2Ax%29%2F-1\" Divide both sides by -1.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Which breaks down and reduces to
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-5%2B3%2Ax\" Now we've fully isolated y
\n" ); document.write( "
\n" ); document.write( " Since y equals \"-5%2B3%2Ax\" we can substitute the expression \"-5%2B3%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"7%2Ax%2B-2%2Ahighlight%28%28-5%2B3%2Ax%29%29=15\" Replace y with \"-5%2B3%2Ax\". Since this eliminates y, we can now solve for x.
\n" ); document.write( "
\n" ); document.write( " \"7%2Ax-2%2A%28-5%29-2%283%29x=15\" Distribute -2 to \"-5%2B3%2Ax\"
\n" ); document.write( "
\n" ); document.write( " \"7%2Ax%2B10-6%2Ax=15\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"7%2Ax%2B10-6%2Ax=15\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " \"7%2Ax-6%2Ax=15-10\" Subtract \"10\" from both sides
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"7%2Ax-6%2Ax=5\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax=5\" Now combine the terms on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F1%29%281%2F1%29%29x=%285%2F1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out \"1%2F1\" and isolate x
\n" ); document.write( "
\n" ); document.write( " So when we multiply \"5%2F1\" and \"1%2F1\" (and simplify) we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=5\" <---------------------------------One answer
\n" ); document.write( "
\n" ); document.write( " Now that we know that \"x=5\", lets substitute that in for x to solve for y
\n" ); document.write( "
\n" ); document.write( " \"7%285%29-2%2Ay=15\" Plug in \"x=5\" into the 2nd equation
\n" ); document.write( "
\n" ); document.write( " \"35-2%2Ay=15\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ay=15-35\"Subtract \"35\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ay=-20\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F-2%29%28-2%29%29%2Ay=%28-20%2F1%29%281%2F-2%29\" Multiply both sides by \"1%2F-2\". This will cancel out -2 on the left side.
\n" ); document.write( "
\n" ); document.write( " \"y=-20%2F-2\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=10\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So this is the other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=10\"<---------------------------------Other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our solution is
\n" ); document.write( "
\n" ); document.write( " \"x=5\" and \"y=10\"
\n" ); document.write( "
\n" ); document.write( " which can also look like
\n" ); document.write( "
\n" ); document.write( " (\"5\",\"10\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-1%2Ay=5\"
\n" ); document.write( " \"7%2Ax-2%2Ay=15\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"3%2Ax-1%2Ay=5\" (red) and \"7%2Ax-2%2Ay=15\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"5\",\"10\"). This verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " -----------------------------------------------------------------------------------------------
\n" ); document.write( " Check:
\n" ); document.write( "
\n" ); document.write( " Plug in (\"5\",\"10\") into the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=5\" and \"y=10\". Now plug those values into the equation \"3%2Ax-1%2Ay=5\"
\n" ); document.write( "
\n" ); document.write( " \"3%2A%285%29-1%2A%2810%29=5\" Plug in \"x=5\" and \"y=10\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"15-10=5\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5=5\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5=5\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"5\",\"10\") satisfies \"3%2Ax-1%2Ay=5\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=5\" and \"y=10\". Now plug those values into the equation \"7%2Ax-2%2Ay=15\"
\n" ); document.write( "
\n" ); document.write( " \"7%2A%285%29-2%2A%2810%29=15\" Plug in \"x=5\" and \"y=10\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"35-20=15\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"15=15\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"15=15\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"5\",\"10\") satisfies \"7%2Ax-2%2Ay=15\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the solution (\"5\",\"10\") satisfies the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-1%2Ay=5\"
\n" ); document.write( " \"7%2Ax-2%2Ay=15\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " this verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2.
\n" ); document.write( "\"3a=2-b\"
\n" ); document.write( "\"3a=7-b\"
\n" ); document.write( "---------------\r
\n" ); document.write( "\n" ); document.write( "\"3a%2Bb=2\"......let \"x=a\" and \"y=b\"
\n" ); document.write( "\"3a%2Bb=7\"\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a linear system of equations by subsitution

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B1%2Ay=2\"
\n" ); document.write( " \"3%2Ax%2B1%2Ay=7\"
\n" ); document.write( "
\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
\n" ); document.write( "
\n" ); document.write( " Solve for y for the first equation
\n" ); document.write( "
\n" ); document.write( " \"1%2Ay=2-3%2Ax\"Subtract \"3%2Ax\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"y=%282-3%2Ax%29\" Divide both sides by 1.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Which breaks down and reduces to
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=2-3%2Ax\" Now we've fully isolated y
\n" ); document.write( "
\n" ); document.write( " Since y equals \"2-3%2Ax\" we can substitute the expression \"2-3%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B1%2Ahighlight%28%282-3%2Ax%29%29=7\" Replace y with \"2-3%2Ax\". Since this eliminates y, we can now solve for x.
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B1%2A%282%29%2B1%28-3%29x=7\" Distribute 1 to \"2-3%2Ax\"
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B2-3%2Ax=7\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B2-3%2Ax=7\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-3%2Ax=7-2\" Subtract \"2\" from both sides
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-3%2Ax=5\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"0%2Ax=5\" Now combine the terms on the left side.
\n" ); document.write( " \"0%2F1=5%2F1\" Since this expression is not true, we have an inconsistency.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So there are no solutions. The simple reason is the 2 equations represent 2 parallel lines that will never intersect. Since no intersections occur, no solutions exist.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"+graph%28+500%2C+600%2C+-6%2C+5%2C+-10%2C+10%2C+%282-3%2Ax%29%2F1%2C+%287-3%2Ax%29%2F1+%29+\" graph of \"3%2Ax%2B1%2Ay=2\" (red) and \"3%2Ax%2B1%2Ay=7\" (green) (hint: you may have to solve for y to graph these)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations are parallel and will never intersect. So this system is inconsistent

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3.\r
\n" ); document.write( "\n" ); document.write( "\"3x-y=0\"
\n" ); document.write( "\"2x-y=1\"\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a linear system of equations by subsitution

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-1%2Ay=0\"
\n" ); document.write( " \"2%2Ax-1%2Ay=1\"
\n" ); document.write( "
\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
\n" ); document.write( "
\n" ); document.write( " Solve for y for the first equation
\n" ); document.write( "
\n" ); document.write( " \"-1%2Ay=0-3%2Ax\"Subtract \"3%2Ax\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"y=%280-3%2Ax%29%2F-1\" Divide both sides by -1.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Which breaks down and reduces to
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=0%2B3%2Ax\" Now we've fully isolated y
\n" ); document.write( "
\n" ); document.write( " Since y equals \"0%2B3%2Ax\" we can substitute the expression \"0%2B3%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"2%2Ax%2B-1%2Ahighlight%28%280%2B3%2Ax%29%29=1\" Replace y with \"0%2B3%2Ax\". Since this eliminates y, we can now solve for x.
\n" ); document.write( "
\n" ); document.write( " \"2%2Ax-1%2A%280%29-1%283%29x=1\" Distribute -1 to \"0%2B3%2Ax\"
\n" ); document.write( "
\n" ); document.write( " \"2%2Ax%2B0-3%2Ax=1\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"2%2Ax%2B0-3%2Ax=1\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " \"2%2Ax-3%2Ax=1%2B0\"Add \"0\" to both sides
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"2%2Ax-3%2Ax=1\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"-1%2Ax=1\" Now combine the terms on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F-1%29%28-1%2F1%29%29x=%281%2F1%29%281%2F-1%29\" Multiply both sides by \"1%2F-1\". This will cancel out \"-1%2F1\" and isolate x
\n" ); document.write( "
\n" ); document.write( " So when we multiply \"1%2F1\" and \"1%2F-1\" (and simplify) we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=-1\" <---------------------------------One answer
\n" ); document.write( "
\n" ); document.write( " Now that we know that \"x=-1\", lets substitute that in for x to solve for y
\n" ); document.write( "
\n" ); document.write( " \"2%28-1%29-1%2Ay=1\" Plug in \"x=-1\" into the 2nd equation
\n" ); document.write( "
\n" ); document.write( " \"-2-1%2Ay=1\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"-1%2Ay=1%2B2\"Add \"2\" to both sides
\n" ); document.write( "
\n" ); document.write( " \"-1%2Ay=3\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F-1%29%28-1%29%29%2Ay=%283%2F1%29%281%2F-1%29\" Multiply both sides by \"1%2F-1\". This will cancel out -1 on the left side.
\n" ); document.write( "
\n" ); document.write( " \"y=3%2F-1\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-3\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So this is the other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-3\"<---------------------------------Other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our solution is
\n" ); document.write( "
\n" ); document.write( " \"x=-1\" and \"y=-3\"
\n" ); document.write( "
\n" ); document.write( " which can also look like
\n" ); document.write( "
\n" ); document.write( " (\"-1\",\"-3\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-1%2Ay=0\"
\n" ); document.write( " \"2%2Ax-1%2Ay=1\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"3%2Ax-1%2Ay=0\" (red) and \"2%2Ax-1%2Ay=1\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"-1\",\"-3\"). This verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " -----------------------------------------------------------------------------------------------
\n" ); document.write( " Check:
\n" ); document.write( "
\n" ); document.write( " Plug in (\"-1\",\"-3\") into the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=-1\" and \"y=-3\". Now plug those values into the equation \"3%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( " \"3%2A%28-1%29-1%2A%28-3%29=0\" Plug in \"x=-1\" and \"y=-3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"-3%2B3=0\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"0=0\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"0=0\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"-1\",\"-3\") satisfies \"3%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=-1\" and \"y=-3\". Now plug those values into the equation \"2%2Ax-1%2Ay=1\"
\n" ); document.write( "
\n" ); document.write( " \"2%2A%28-1%29-1%2A%28-3%29=1\" Plug in \"x=-1\" and \"y=-3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"-2%2B3=1\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1=1\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1=1\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"-1\",\"-3\") satisfies \"2%2Ax-1%2Ay=1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the solution (\"-1\",\"-3\") satisfies the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-1%2Ay=0\"
\n" ); document.write( " \"2%2Ax-1%2Ay=1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " this verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

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