document.write( "Question 672714: 3{ [4 (x-1) +5] - [ 2 ( 2x-1) +5]}\r
\n" ); document.write( "\n" ); document.write( "i know \"pemdas\", but i cant figure this out. I dont get when to apply the distributive law, and how this cancles out. I guess the order us messing me up. \n" ); document.write( "
Algebra.Com's Answer #418269 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Always work from the inside out
\n" ); document.write( "\"+3%2A%28+%28+4%2A%28x-1%29+%2B+5+%29+-+%28+2%2A%28+2x-1+%29+%2B+5+%29%29+\"
\n" ); document.write( "One check that you can do is just count the
\n" ); document.write( "number of ( 's and the number of ) 's -they
\n" ); document.write( "should be the same. In this problem, they
\n" ); document.write( "both are 5.
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\n" ); document.write( "first step:
\n" ); document.write( "\"+3%2A%28+%28+4x+-+4+%2B+5+%29+-+%28+4x+-+2+%2B+5+%29%29+\"
\n" ); document.write( "Now simplify:
\n" ); document.write( "\"+3%2A%28%28+4x+%2B+1+%29+-+%28+4x+%2B+3+%29%29+\"
\n" ); document.write( "The \"+4x+%2B+1+\" doesn't really need to be in
\n" ); document.write( "parentheses at this point, also, do the
\n" ); document.write( "subtraction using distributive law.
\n" ); document.write( "\"+3%2A%28+4x+%2B+1+-+4x+-+3+%29+\"
\n" ); document.write( "\"+3%2A%28+-2+%29+\"
\n" ); document.write( "\"+-6+\"
\n" ); document.write( "Note that it doesn't matter what \"+x+\" is,
\n" ); document.write( "the result is still \"+-6+\"
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