document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=672687>Question 672687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could I please have some help with this problem. Thank you.\r<BR>\n" );
document.write( "\n" );
document.write( "Find the area under the standard normal curve for the following:<BR>\n" );
document.write( "(A) P(z > 0.90)\r<BR>\n" );
document.write( "\n" );
document.write( "(B) P(-1.17 < z < 0)\r<BR>\n" );
document.write( "\n" );
document.write( "(C) P(-0.58 < z < 1.57)\r<BR>\n" );
document.write( "\n" );
document.write( "table is a \"cumulative standard normal table (so it gives area to the left of the z-score) and has positive and negative z-scores shown\". </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418262 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I suggest you purchase a TI-84+ calculator.<BR>\n" );
document.write( "-------------------------\r<BR>\n" );
document.write( "\n" );
document.write( "(A) P(z > 0.90) = normalcdf(0.90,100) = 0.1841<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "normalcdf sums up the area under the normal curve <BR>\n" );
document.write( "over the z-interval [0.9,100]<BR>\n" );
document.write( "-------------- <BR>\n" );
document.write( "(B) P(-1.17 < z < 0) = normalcdf(-1.17,0) = 0.3790<BR>\n" );
document.write( "normalcdf sums up the area under the normal curve<BR>\n" );
document.write( "over the z-interval (-1.17,0)<BR>\n" );
document.write( "------------------ <BR>\n" );
document.write( "(C) P(-0.58 < z < 1.57) = normalcdf(-0.58,1.57) = 0.4649 <BR>\n" );
document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==============<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );