document.write( "Question 672642: An oil tanker can be emptied by a main pump in 4hours an auxiliary pump can empty it in 9 hrs if the main pump is started at 9 am when should the auxiliary pump be started so the tanker will be empty by noon? \n" ); document.write( "
Algebra.Com's Answer #418244 by josmiceli(19441)\"\" \"About 
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From 9 AM to noon is 3 hrs
\n" ); document.write( "Let \"+x+\" = number of hours the main pump
\n" ); document.write( "is used pumping by itself
\n" ); document.write( "\"+3+-+x+\" = number of hours that both pumps are pumping
\n" ); document.write( "---------------
\n" ); document.write( "The main pump's rate of pumping is ( 1 tanker / 4 hrs )
\n" ); document.write( "the auxilliary pump's rate is ( 1 tanker / 9 hrs )
\n" ); document.write( "----------------
\n" ); document.write( "( fraction of tanker pumped in x hrs ) +
\n" ); document.write( "( fraction pumped by both pumps in 3-x hrs ) = 1 whole tanker pumped
\n" ); document.write( "\"+%281%2F4%29%2Ax+%2B+%28+1%2F9+%2B+1%2F4+%29%2A%28+3-x+%29+=+1+\"
\n" ); document.write( "Multiply both sides by \"+36+\"
\n" ); document.write( "\"+9x+%2B+%28+4+%2B+9%29%2A%28+3-x+%29+=+36+\"
\n" ); document.write( "\"+9x+%2B+13%2A%28+3-x+%29+=+36+\"
\n" ); document.write( "\"+9x+%2B+39+-+13x+=+36+\"
\n" ); document.write( "\"+-4x+=+-3+\"
\n" ); document.write( "\"+x+=+.75+\"
\n" ); document.write( "\"+3+-+x+=+2.25+\"
\n" ); document.write( "The auxiliary pump should be started at 9:45
\n" ); document.write( "check answer:
\n" ); document.write( "In 3/4 of an hour the main pump empties
\n" ); document.write( "\"+%281%2F4%29%2A%283%2F4%29+=+3%2F16+\" of the tanker
\n" ); document.write( "In 2.25 hrs, both together empty
\n" ); document.write( "\"+%28+1%2F4+%2B+1%2F9+%29%2A%289%2F4%29+\"
\n" ); document.write( "\"+%28+9%2F36+%2B+4%2F36+%29%2A81%2F36+\"
\n" ); document.write( "\"+%28+13%2F36+%29%2A%28+81%2F36+%29+\"
\n" ); document.write( "\"+%28+13%2A81+%29+%2F+%28+36%5E2+%29+\"
\n" ); document.write( "\"+1053+%2F+1296+\"
\n" ); document.write( "\"+13%2F16+\"
\n" ); document.write( "and \"+13%2F16+%2B+3%2F16+=+1+\"
\n" ); document.write( "OK
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