document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60867>Question 60867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how can i solve this system by substitution.<BR>\n" );
document.write( "	2x + 2y = 0<BR>\n" );
document.write( "	          y = 4x + 0<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41821 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=4x+0 now substitute (4x+0) for y in the other equation we get<BR>\n" );
document.write( "2x+2(4x+0)=0<BR>\n" );
document.write( "2x+8x=0<BR>\n" );
document.write( "10x=0<BR>\n" );
document.write( "x=0 solution<BR>\n" );
document.write( "y=4*0+0<BR>\n" );
document.write( "y=0 solution </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );