document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=672233>Question 672233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a ball with a diameter of 20 is partially submerged in a pool full of water so the top of the ball is 5 inches above the surface. The intersection of the ball and the waters surface forms a circle, find its circumfrence. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418181 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  a ball with a diameter of 20 is partially submerged in a pool full of water so the top of the ball is 5 inches above the surface.<BR>\n" );
document.write( " The intersection of the ball and the waters surface forms a circle, find its circumference.<BR>\n" );
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document.write( "A chord (c) on the circle formed in the center of the ball, would be the diameter of the circle on the surface of the water.<BR>\n" );
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document.write( "Find the length of half the chord using Pythagoras, mult by 2:<BR>\n" );
document.write( "(the radius is the hypotenuse, one side is the center dist to the chord)<BR>\n" );
document.write( " c = 2 * <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2810%5E2+-+5%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2810%5E2+-+5%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " c = 17.32 is the chord and the diameter of circle on the surface<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "17.32 * pi = 54.4 inches<BR>\n" );
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document.write( "  </SPAN>\n" );
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