document.write( "Question 672551: Find an equation(s) of the line(s) containing (5, 1) and at a distance 1 from the origin. \n" ); document.write( "
Algebra.Com's Answer #418178 by Alan3354(69443)\"\" \"About 
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Find an equation(s) of the line(s) containing (5,1) and at a distance 1 from the origin.
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\n" ); document.write( "--> 2 lines thru the point and tangent to the circle \"x%5E2+%2B+y%5E2+=+1\"
\n" ); document.write( "One line is parallel to the x-axis
\n" ); document.write( "y = 1 *** eqn of one of the lines
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\n" ); document.write( "The slope of the line from (5,1) to the Origin (center of the 1st circle) = 1/5
\n" ); document.write( "= tangent of the angle between the line and the x-axis.
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\n" ); document.write( "The line from (0,0) to (5,1) is the bisector of the 2 tangent lines thru (5,1).
\n" ); document.write( "--> the angle of the 2nd line and the x-axis = 2x the bisector
\n" ); document.write( "angle = 2*atan(1/5)
\n" ); document.write( "slope = tan(2*atan(1/5)) = 5/12
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\n" ); document.write( "Y = mx + b
\n" ); document.write( "Use the point (5,1) and the slope = 5/12
\n" ); document.write( "1 = (5/12)*5 + b
\n" ); document.write( "b = -13/12
\n" ); document.write( "2nd eqn y = (5/12)x - 13/12
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\n" ); document.write( "y = 1 & y = 5x/12 - 13/12\r
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