document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=672511>Question 672511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man can complete a piece of work in 9 days but with the help of his son, he can do it in 6 days.the taken by his son to do it alone is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418125 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418125\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a man can complete a piece of work in 9 days but with the help of his son, he can do it in 6 days.the taken by his son to do it alone is<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = time (days) it takes the son alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "6(1/9 + 1/x) = 1<BR>\n" );
document.write( "multiplying both sides 9x:<BR>\n" );
document.write( "6(x + 9) = 9x<BR>\n" );
document.write( "6x + 54 = 9x<BR>\n" );
document.write( "54 = 3x<BR>\n" );
document.write( "18 days = x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );