document.write( "Question 672461: How many liters of a 12% acid solution and a 20% acid solution should be mixed in order to obtain 4 liters of a 15% acid solution? \n" ); document.write( "
Algebra.Com's Answer #418064 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Acid solution I 12 ---------------- x liters
\n" ); document.write( "Acid solution II 20 ------ 4 - x liters
\n" ); document.write( "Mixture 15 ---------------- 4
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\n" ); document.write( "12x+20(4-x)=15*4
\n" ); document.write( "1200x+2000(4-x) =6000
\n" ); document.write( "1200x+8000-2000 x=6000
\n" ); document.write( "1200x- 2000x=6000 -8000
\n" ); document.write( "-800 x = -2000
\n" ); document.write( "/ -800
\n" ); document.write( "x=2.5 liters 12.00% Acid solution I
\n" ); document.write( "1.5 liters 20.00% Acid solution II
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\n" ); document.write( "m.ananth@hotmail.ca
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