document.write( "Question 672461: How many liters of a 12% acid solution and a 20% acid solution should be mixed in order to obtain 4 liters of a 15% acid solution? \n" ); document.write( "
Algebra.Com's Answer #418064 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Acid solution I 12 ---------------- x liters \n" ); document.write( "Acid solution II 20 ------ 4 - x liters \n" ); document.write( "Mixture 15 ---------------- 4 \n" ); document.write( " \n" ); document.write( "12x+20(4-x)=15*4 \n" ); document.write( "1200x+2000(4-x) =6000 \n" ); document.write( "1200x+8000-2000 x=6000 \n" ); document.write( "1200x- 2000x=6000 -8000 \n" ); document.write( "-800 x = -2000 \n" ); document.write( "/ -800 \n" ); document.write( "x=2.5 liters 12.00% Acid solution I \n" ); document.write( "1.5 liters 20.00% Acid solution II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |