document.write( "Question 672468: An investment of 10,800 is deposited into two simple interest accounts. On one account the annual simple interest rate is 11.2%. On the other, the annual simple interest rate is 14%. How much should be invested in each account so that the interest earned is the same? \n" ); document.write( "

Algebra.Com's Answer #418062 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+a+\"$ = amount invested @ 11.2%
\n" ); document.write( "Let $\"+b+\"$ = amount invested @ 14%
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"+a+%2B+b+=+10800+\"$
\n" ); document.write( "(2) $\"+.112a+=+.14b+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "(2) $\"+112a+=+140b+\"$
\n" ); document.write( "(2) $\"+a+=+%28140%2F112%29%2Ab+\"$
\n" ); document.write( "(2) $\"+a+=+1.25b+\"$
\n" ); document.write( "Substitute this result into (1)
\n" ); document.write( "(1) $\"+1.25b+%2B+b+=+10800+\"$
\n" ); document.write( "(1) $\"+2.25b+=+10800+\"$
\n" ); document.write( "(1) $\"+b+=+4800+\"$
\n" ); document.write( "and, since
\n" ); document.write( "(1) $\"+a+%2B+b+=+10800+\"$
\n" ); document.write( "(1) $\"+a+%2B+4800+=+10800+\"$
\n" ); document.write( "(1) $\"+a+=+6000+\"$
\n" ); document.write( "$6,000 should be invested @ 11.2%
\n" ); document.write( "$4,800 should be invested @ 14%
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+.112a+=+.14b+\"$
\n" ); document.write( "(2) $\"+.112%2A6000+=+.14%2A4800+\"$
\n" ); document.write( "(2) $\"+672+=+672+\"$
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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