document.write( "Question 672437: Find an equation of the circle that has center (-1, 1)and passes through(-5,6) \n" ); document.write( "
Algebra.Com's Answer #418040 by DrBeeee(684)\"\" \"About 
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Equation of circle is
\n" ); document.write( "(1) (x-a)^2 + (y-b)^2 = r^2, where (a,b) are the coordinates of the center of the circle and r is the radius. In your case you have
\n" ); document.write( "(2) (x+1)^2 + (y-1)^2 = r^2
\n" ); document.write( "To find r substitute the point (-5,6) into (2) and get
\n" ); document.write( "(3) (-5+1)^2 + (6-1)^2 = r^2 or
\n" ); document.write( "(4) 16 + 25 = r^2 or
\n" ); document.write( "(5) r^2 = 41
\n" ); document.write( "The equation of the circle is
\n" ); document.write( "(6) (x+1)^2 + (y-1)^2 = 41
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