document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=672425>Question 672425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man invests $5500 dollars in three accounts that pay 5%, 8%, and 9% in annual interest respectively. He has two times as much money invested at 9% as he does at 8%. If the total interest earned for the year is $449, how much is invested at 5%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418037 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8%-------------------x<BR>\n" );
document.write( "9%-------------------2x\r<BR>\n" );
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document.write( "Balance @\r<BR>\n" );
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document.write( "5%-------------------(5500-3x)\r<BR>\n" );
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document.write( "Interest = 449\r<BR>\n" );
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document.write( "0.08x+0.09(2x)+0.05(5500-3x)=449\r<BR>\n" );
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document.write( "Multiply by 100<BR>\n" );
document.write( "8x+18x+27500-15x=44900\r<BR>\n" );
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document.write( "11x=44900-27500<BR>\n" );
document.write( "11x=17400<BR>\n" );
document.write( "x= 1581.82................8%<BR>\n" );
document.write( "2x=3163.64.................9%<BR>\n" );
document.write( "754.55.....................5% </SPAN>\n" );
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