document.write( "Question 672425: A man invests $5500 dollars in three accounts that pay 5%, 8%, and 9% in annual interest respectively. He has two times as much money invested at 9% as he does at 8%. If the total interest earned for the year is $449, how much is invested at 5%? \n" ); document.write( "

Algebra.Com's Answer #418036 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = amount invested @ 8%
\n" ); document.write( " $\"+2x+\"$ = amount invested @ 9%
\n" ); document.write( "Let $\"+y+\"$ = amount invested @ 5%
\n" ); document.write( "--------------
\n" ); document.write( "(1) $\"+x+%2B+2x+%2B+y+=+5500+\"$
\n" ); document.write( "(2) $\"+.08x+%2B+.09%2A%282x%29+%2B+.05y+=+449+\"$
\n" ); document.write( "--------------
\n" ); document.write( "(1) $\"+3x+%2B+y+=+5500+\"$
\n" ); document.write( "(1) $\"+y+=+5500+-+3x+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+.08x+%2B+.18x+%2B+.05y+=+449+\"$
\n" ); document.write( "(2) $\"+.08x+%2B+.18x+%2B+.05%2A%28+5500+-+3x+%29+=+449+\"$
\n" ); document.write( "(2) $\"+.26x+%2B+275+-+.15x+=+449+\"$
\n" ); document.write( "(2) $\"+.11x+=+449+-+275+\"$
\n" ); document.write( "(2) $\"+.11x+=+174+\"$
\n" ); document.write( "(2) $\"+x+=+1581.82+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+y+=+5500+-+3x+\"$
\n" ); document.write( "(1) $\"+y+=+5500+-+3%2A1581.82+\"$
\n" ); document.write( "(2) $\"+y+=+5500+-+4745.45+\"$
\n" ); document.write( "(2) $\"+y+=+754.55+\"$
\n" ); document.write( "$754.55 was invested @ 5%
\n" ); document.write( "check:
\n" ); document.write( " $\"+x+=+1581.82+\"$
\n" ); document.write( " $\"+2x+=+3163.64\"$
\n" ); document.write( " $\"+1581.82+%2B+3163.64+%2B+754.55+=+5500+\"$
\n" ); document.write( " $\"+5500.01+=+5500+\"$
\n" ); document.write( "close enough
\n" ); document.write( "(2) $\"+.08x+%2B+.09%2A%282x%29+%2B+.05y+=+449+\"$
\n" ); document.write( "(2) $\"+.08%2A1581.82+%2B+.09%2A3163.64%2B+.05%2A754.55+=+449+\"$
\n" ); document.write( "(2) $\"+126.55+%2B+284.73+%2B+37.73+=+449+\"$
\n" ); document.write( "(2) $\"+449.01+=+449+\"$
\n" ); document.write( "close enough\r
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\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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