document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=672426>Question 672426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The daily demand for gas at Good’s Gas station is normally distributed with a mean of 1812  gallons and a standard deviation of 254 gallons. \r<BR>\n" );
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document.write( "(a) 	What is the probability that the demand for gas will exceed 2000 gallons on any day?<BR>\n" );
document.write( "(b)  What is the probability that the demand for gas in a day will be between 1500 and 2000 gallons?<BR>\n" );
document.write( "(c)  What is the probability that the demand for gas will exceed 1500 gallons on any day?<BR>\n" );
document.write( "(d) how much gasoline should the station have on hand at the beginning of the day so that the probability of running out of gas that day is only 1%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418035 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The daily demand for gas at Good’s Gas station is normally distributed with a mean of 1812 gallons and a standard deviation of 254 gallons. <BR>\n" );
document.write( "(a) What is the probability that the demand for gas will exceed 2000 gallons on any day?<BR>\n" );
document.write( "z(2000) = (2000-1812)/254 = 0.7402<BR>\n" );
document.write( "P(x > 2000) = P(z > 0.7402) = normalcdf(0.7402,100) = 0.2296<BR>\n" );
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document.write( "(b) What is the probability that the demand for gas in a day will be between 1500 and 2000 gallons?<BR>\n" );
document.write( "z(1500) = (1500-1812)/254 = -1.2283<BR>\n" );
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document.write( "P(1500<= x <=2000) = P(-1.2283<= z <=0.2296) = 0.4811<BR>\n" );
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document.write( "(c) What is the probability that the demand for gas will exceed 1500 gallons on any day?<BR>\n" );
document.write( "Ans: P(-1.2283,100) = 0.8903<BR>\n" );
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document.write( "(d) how much gasoline should the station have on hand at the beginning of the day so that the probability of running out of gas that day is only 1%?<BR>\n" );
document.write( "Find the z-value with a right tail of 1%.<BR>\n" );
document.write( "invNorm(0.99) = 2.3263<BR>\n" );
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document.write( "Find the corresponding gas value using x = z*s+u<BR>\n" );
document.write( "x = 2.3263*254+1812 = 2402.89 gallons<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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