document.write( "Question 671952: Solve the equation for solutions over the interval [0,2pi)\r
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document.write( "cot^2 theta= (-5) +4csc theta\r
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document.write( "I believe I have solved to the last step which is where I am stuck. \r
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document.write( "This is what I have done so far (please forgive all the steps if I do not do them I will get lost and not understand what happened along the way):\r
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document.write( "0= (-5) +4csc theta - csc^2 theta +1
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document.write( "0= (-5) + 1 + 4csc theta - csc ^2 theta
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document.write( "0= (-4) + 4csc theta - csc^2 theta
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document.write( "0= -csc^2 theta + 4csc theta - 4
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document.write( "0= (csc theta -2)(csc theta +2)\r
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document.write( "Set both to zero:\r
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document.write( "csc theta-2 = 0
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document.write( "csc theta = 2 (this is where I am stuck...what next?) \r
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document.write( "csc theta+2=0
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document.write( "csc theta = -2 (again stuck here)\r
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document.write( "Thank you in advance :) \n" );
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Algebra.Com's Answer #417975 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Solve the equation for solutions over the interval [0,2pi) \n" ); document.write( "cot^2 theta= (-5) +4csc theta \n" ); document.write( "use x for theta \n" ); document.write( "cot^2x=-5+4cscx \n" ); document.write( "cos^2x/sin^2x=-5+4/sinx \n" ); document.write( "multiply both sides by sin^2x \n" ); document.write( "cos^2x=-5sin^2x+4sinx \n" ); document.write( "1-sin^2x=-5sin^2x+4sinx \n" ); document.write( "4sin^2x-4sinx+1=0 \n" ); document.write( "(2sinx-1)(2sinx-1)=0 \n" ); document.write( "2sinx-1=0 \n" ); document.write( "sinx=1/2 \n" ); document.write( "x=π/6, 5π/6 (multiplicity 2) \n" ); document.write( " |