document.write( "Question 672324: Please verify by changing the left side only:\r
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document.write( "tan(pi/4-x) = (cosx-sinx)/(cosx+sinx) \n" );
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Algebra.Com's Answer #417933 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Please verify by changing the left side only: \n" ); document.write( "tan(pi/4-x) = (cosx-sinx)/(cosx+sinx) \n" ); document.write( "** \n" ); document.write( "Identity: tan(s-t)=(tan s-tan t)/(1+tan s tan t) \n" ); document.write( "tan(π/4-x)=(tan π/4-tan x)/(1+tan π/4 tan x) \n" ); document.write( "tan π/4=1 \n" ); document.write( "=(1-tan x)/(1+tan x) \n" ); document.write( "=[1-(sin x/cos x)]/[1+(sin x/cos x)] \n" ); document.write( "=[(cos x-sin x)/cos x)]/[(cos x+sin x)/cos x)] \n" ); document.write( "cos x in denominator cancels out \n" ); document.write( "=(cos x-sin x)/(cos x+sin x) \n" ); document.write( "verified: left side=right side \n" ); document.write( " |