document.write( "Question 672324: Please verify by changing the left side only:\r
\n" ); document.write( "\n" ); document.write( "tan(pi/4-x) = (cosx-sinx)/(cosx+sinx)
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Algebra.Com's Answer #417933 by lwsshak3(11628)\"\" \"About 
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Please verify by changing the left side only:
\n" ); document.write( "tan(pi/4-x) = (cosx-sinx)/(cosx+sinx)
\n" ); document.write( "**
\n" ); document.write( "Identity: tan(s-t)=(tan s-tan t)/(1+tan s tan t)
\n" ); document.write( "tan(π/4-x)=(tan π/4-tan x)/(1+tan π/4 tan x)
\n" ); document.write( "tan π/4=1
\n" ); document.write( "=(1-tan x)/(1+tan x)
\n" ); document.write( "=[1-(sin x/cos x)]/[1+(sin x/cos x)]
\n" ); document.write( "=[(cos x-sin x)/cos x)]/[(cos x+sin x)/cos x)]
\n" ); document.write( "cos x in denominator cancels out
\n" ); document.write( "=(cos x-sin x)/(cos x+sin x)
\n" ); document.write( "verified: left side=right side
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