document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60648>Question 60648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve:  17-4x/12=5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " An 80-pound grass seed mixture is 30% bluegrass seed. How many pounds of seed containing no bluegrass seed (0%) should be added to the seed mixture for a resulting blend that is 20% bluegrass seed?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41793 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Solve%3A+17-4x%2F12=5 ALIGN=MIDDLE  ALT=\"Solve%3A+17-4x%2F12=5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ":<BR>\n" );
document.write( "Get rid of the denominator, mult eq by 12, results:<BR>\n" );
document.write( "12(17) - 4x = 12(5)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "204 - 4x = 60<BR>\n" );
document.write( "-4x = 60 - 204<BR>\n" );
document.write( "-4x = -144<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Divide both sides by -4<BR>\n" );
document.write( "x = -144/-4<BR>\n" );
document.write( "x = 36 <BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "An 80-pound grass seed mixture is 30% bluegrass seed. How many pounds of seed containing no bluegrass seed (0%) should be added to the seed mixture for a resulting blend that is 20% bluegrass seed?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let x = amt of of \"no bluegrass\" seed<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Write a per cent blue grass equation:<BR>\n" );
document.write( ".30(80) + 0(x) = .20(80+x)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "24 + 0 = 16 + .2x<BR>\n" );
document.write( "24 - 16 = .2x<BR>\n" );
document.write( "8 = .2x<BR>\n" );
document.write( "x = 8/.2<BR>\n" );
document.write( "x = 40 lb of \"no bluegrass\" seed\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );