document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60828>Question 60828</A>: <I><SPAN STYLE=\"word-break: break-all;\">  When graphing a line that has slope 2/3 and passes through the point (1, -4, ehich of the following is a second point on the line?\r<BR>\n" );
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document.write( "A) (3,-1)  B) (4-2)  C) (-1,1)  D) (3,8)  E) (2,3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41791 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=mX+b<BR>\n" );
document.write( "-4=2/3*1+b<BR>\n" );
document.write( "-4=2/3+b<BR>\n" );
document.write( "b=-4-2/3<BR>\n" );
document.write( "b=-14/3 THUS WE HAVE A Y INTERCEPT OF -14/3<BR>\n" );
document.write( "Y=2/3X-14/3<BR>\n" );
document.write( "-2=2/3*4-14/3<BR>\n" );
document.write( "-2=8/3-14/3<BR>\n" );
document.write( "-2=-6/3<BR>\n" );
document.write( "-2=-2 PROOF THAT B)4,-2 IS A POINT ON THIS LINE.\r<BR>\n" );
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