document.write( "Question 672301: How many ml of 40 percent acid should be added to pure acid to make 75 ml of 65 percent acid? \n" ); document.write( "

Algebra.Com's Answer #417900 by sachi(548) $\"\"$ $\"About$

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let x ml of 40 % acid should be added to (75-x)ml 100% pure acid to make 75 ml of 65 % acid
\n" ); document.write( "so (40x/100)+(75-x)*100/100=65*75/100
\n" ); document.write( "or 40x+100(75-x)=65*75
\n" ); document.write( "or 40x-100x=65*75-100*75=75(65-100)=-75*35
\n" ); document.write( "or -60x=-75*35
\n" ); document.write( "or x=75*35/60=43.75 ml ans \n" ); document.write( "

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