document.write( "Question 60822This question is from textbook Elementry and Intermediate Algebra
\n" ); document.write( ": Pat travels 70 miles on her milk route and Bob travels 75 miles on his route. Pat travels 5 miles per hour slower than Bob, and her route takes ½ hour longer than Bob’s. Find the speed at which each of them is traveling. \n" ); document.write( "
Algebra.Com's Answer #41787 by Nate(3500)\"\" \"About 
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Pat's rate: b - 5
\n" ); document.write( "Bob's rate: b
\n" ); document.write( "Pat's time: 1.5t
\n" ); document.write( "Bob's time: t
\n" ); document.write( "Time * Rate = Distance
\n" ); document.write( "(b - 5)(1.5t) = 70
\n" ); document.write( "(b)(t) = 75
\n" ); document.write( "Use bob's formula:
\n" ); document.write( "t = 75/b
\n" ); document.write( "Substitute:
\n" ); document.write( "(b - 5)(1.5(75/b)) = 70
\n" ); document.write( "(b - 5)(112.5) = 70b
\n" ); document.write( "112.5b - 562.5 = 70b
\n" ); document.write( "42.5b = 562.5
\n" ); document.write( "About 13.24 (Bob's Rate)
\n" ); document.write( "Pat's Rate is about 8.24
\n" ); document.write( "~> Bob's time: 5.66
\n" ); document.write( "~> Pat's time: 8.5
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