document.write( "Question 672211: if A walked 1km/hr faster then A would have taken 10 min less to walk 2km/hr. find the speed of A \n" ); document.write( "
Algebra.Com's Answer #417857 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! if A walked 1km/hr faster then A would have taken 10 min less to walk 2km/hr. find the speed of A \n" ); document.write( ": \n" ); document.write( "let s = the speed of A \n" ); document.write( ": \n" ); document.write( "Change 10 min to 10/60 = 1/6 hr \n" ); document.write( ": \n" ); document.write( "slow time - fast time = 10 min \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "mult by 6s(s+1), cancel the denominators and you have: \n" ); document.write( "6(s+1)*2 - 6s(2) = s(s+1) \n" ); document.write( "12(s+1) - 12s = s^2 + s \n" ); document.write( "12s + 12 - 12s = s^2 + s \n" ); document.write( ": \n" ); document.write( "A quadratic equation \n" ); document.write( "s^2 + s - 12 = 0 \n" ); document.write( ": \n" ); document.write( "Factors to \n" ); document.write( "(s+4)(s-3) = 0 \n" ); document.write( ": \n" ); document.write( "the positive solution is what we want here \n" ); document.write( "s = 3 km/h is his speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( "2/3 - 2/4 = \n" ); document.write( "8/12 - 6/12 = 2/12 = 1/6 \n" ); document.write( " |