document.write( "Question 672211: if A walked 1km/hr faster then A would have taken 10 min less to walk 2km/hr. find the speed of A \n" ); document.write( "
Algebra.Com's Answer #417857 by ankor@dixie-net.com(22740)\"\" \"About 
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if A walked 1km/hr faster then A would have taken 10 min less to walk 2km/hr. find the speed of A
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\n" ); document.write( "let s = the speed of A
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\n" ); document.write( "Change 10 min to 10/60 = 1/6 hr
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\n" ); document.write( "slow time - fast time = 10 min
\n" ); document.write( "\"2%2Fs\" - \"2%2F%28%28s%2B1%29%29\" = \"1%2F6\"
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\n" ); document.write( "mult by 6s(s+1), cancel the denominators and you have:
\n" ); document.write( "6(s+1)*2 - 6s(2) = s(s+1)
\n" ); document.write( "12(s+1) - 12s = s^2 + s
\n" ); document.write( "12s + 12 - 12s = s^2 + s
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\n" ); document.write( "A quadratic equation
\n" ); document.write( "s^2 + s - 12 = 0
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\n" ); document.write( "Factors to
\n" ); document.write( "(s+4)(s-3) = 0
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\n" ); document.write( "the positive solution is what we want here
\n" ); document.write( "s = 3 km/h is his speed
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\n" ); document.write( "Check this
\n" ); document.write( "2/3 - 2/4 =
\n" ); document.write( "8/12 - 6/12 = 2/12 = 1/6
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