document.write( "Question 60790: The line through A(x,5) and B(4,3) is perpendicular to a line whose slope is 3/5. Find the value of x. \n" ); document.write( "
Algebra.Com's Answer #41784 by checkley71(8403)\"\" \"About 
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ALINE PERPENDICULAR TO A LINE WITH A SLOPE OF 3/5 IS A SLOPE OF -5/3
\n" ); document.write( "THUS THE SLOPE PASSING THROUGH THE POINTS (X,5)(4,3) IS -5/3
\n" ); document.write( "(3-5)/(4-X)=-5/3
\n" ); document.write( "-2/(4-X)=-5/3 CROSS MULTIPLYING WE GET
\n" ); document.write( "-6=-5(4-X)
\n" ); document.write( "-6=-20+5X
\n" ); document.write( "5X=-6+20
\n" ); document.write( "5X=14
\n" ); document.write( "X=14/5
\n" ); document.write( "PROOF
\n" ); document.write( "(3-5)/(4-14/5)=-5/3
\n" ); document.write( "-2/(20-14)/5=-5/3
\n" ); document.write( "-2/(6/5)=-5/3
\n" ); document.write( "-2*5/6=-5/3
\n" ); document.write( "-10/6=-5/3
\n" ); document.write( "-5/3=-5/3
\n" ); document.write( " \n" ); document.write( "
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