document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60817>Question 60817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 66m. If the width were doubled and the length were increased by 22m, the perimeter would be 136m. What are the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41783 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=66 THEN 2L=66-2W AND<BR>\n" );
document.write( "2(L+22)+2(2W)=136 SUBSTITUTING (66-2W) THEN<BR>\n" );
document.write( "2L+44+4W=136<BR>\n" );
document.write( "(66-2W)+44+4W=136<BR>\n" );
document.write( "66-2W+44+4W=136<BR>\n" );
document.write( "2W=136-66-44<BR>\n" );
document.write( "2W=26<BR>\n" );
document.write( "W=26/2<BR>\n" );
document.write( "W=13 SOLUTION THEN <BR>\n" );
document.write( "2L=66-2*13<BR>\n" );
document.write( "2L=66-26<BR>\n" );
document.write( "2L=40 SOLUTION<BR>\n" );
document.write( "L=40/2<BR>\n" );
document.write( "L=20<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2(20+22)+2(2*13)=136<BR>\n" );
document.write( "2*42+2*26=136<BR>\n" );
document.write( "84+52=136<BR>\n" );
document.write( "136=136<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );