document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60560>Question 60560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 102. Time swinging. The period T (time in seconds for one complete cycle) of a simple pendulum is related to the length L (in feet) of the pendulum by the formula  8T^2 = pie ^2L.  If a child is on a swing with 10 feet chain, then how long does it take to complete one cycle?   my brain is dead cam some one help my brain rejuvenate :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41779 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8T^2 = pie ^2L <BR>\n" );
document.write( "8T^2 = pie ^2(10) [Substitute 10 for the length (L) and solve]<BR>\n" );
document.write( "T^2=10pi^2/8 [solve for T]<BR>\n" );
document.write( "T^2=12.337 <BR>\n" );
document.write( "sqrt(T^2)=sqrt(12.337)<BR>\n" );
document.write( "T=3.5124 seconds<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check by plugging all of the values back into the original problem and solve]<BR>\n" );
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