document.write( "Question 672039: write the standard form of the equation of the line passing through the points (-3,2) and perpendicular to the line 3x-5y=-15 \n" ); document.write( "
Algebra.Com's Answer #417780 by VirtualMathTutor(26)\"\" \"About 
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First find the slope of the line given by solving for y:\r
\n" ); document.write( "\n" ); document.write( "3x - 5y = -15\r
\n" ); document.write( "\n" ); document.write( "-5y = -15 - 3x\r
\n" ); document.write( "\n" ); document.write( "divide both sides by -5\r
\n" ); document.write( "\n" ); document.write( "y = 3 + \"3%2F5\"x\r
\n" ); document.write( "\n" ); document.write( "Slope m is the coefficient of x which is \"3%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Since our line is perpendicular to the given line, the slope will be the negative reciprocal of the given slope = \"-5%2F3\"\r
\n" ); document.write( "\n" ); document.write( "To find the equation use the formula y - y1 = m(x - x1)\r
\n" ); document.write( "\n" ); document.write( "x1 = -3\r
\n" ); document.write( "\n" ); document.write( "y1 = 2\r
\n" ); document.write( "\n" ); document.write( "y - 2 = \"-5%2F3\"(x - (-3))\r
\n" ); document.write( "\n" ); document.write( "y - 2 = \"-5%2F3\"(x + 3)\r
\n" ); document.write( "\n" ); document.write( "y - 2 = \"-5%2F3\"x - 5\r
\n" ); document.write( "\n" ); document.write( "add 2 to both sides\r
\n" ); document.write( "\n" ); document.write( "y = \"-5%2F3\"x - 3\r
\n" ); document.write( "\n" ); document.write( "In standar form:\r
\n" ); document.write( "\n" ); document.write( "y + \"5%2F3\"x = -3\r
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