document.write( "Question 60812: The length of a rectangle is 5 cm more than 2 times its width. If the area of the rectangle is 78cm^2, find the dimensions of the rectangle to the nearest thousandth.
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document.write( "ac \n" );
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Algebra.Com's Answer #41775 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Hi ac, \n" ); document.write( "The length of a rectangle is 5 cm more than 2 times its width. If the area of the rectangle is 78cm^2, find the dimensions of the rectangle to the nearest thousandth. \n" ); document.write( ": \n" ); document.write( "Let the width be: x \n" ); document.write( "Then the length is: 2x+5 \n" ); document.write( "Area is: 78 cm^2 \n" ); document.write( "Area=length*width \n" ); document.write( ": \n" ); document.write( "78=x(2x+5) \n" ); document.write( "78=2x^2+5x \n" ); document.write( "0=2x^2+5x-78 \n" ); document.write( "This is in standard form: \n" ); document.write( "We can use the quadratic formula to solve it: \n" ); document.write( "a=2, b=5, and c=-78 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "You can ignore the negative dimension. \n" ); document.write( "x=5.119 \n" ); document.write( "The width is: x=5.119 cm \n" ); document.write( "Length is:2x+5=2(5.119)+5=15.238 cm \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |