document.write( "Question 60812: The length of a rectangle is 5 cm more than 2 times its width. If the area of the rectangle is 78cm^2, find the dimensions of the rectangle to the nearest thousandth.
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Algebra.Com's Answer #41775 by funmath(2933)\"\" \"About 
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Hi ac,
\n" ); document.write( "The length of a rectangle is 5 cm more than 2 times its width. If the area of the rectangle is 78cm^2, find the dimensions of the rectangle to the nearest thousandth.
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\n" ); document.write( "Let the width be: x
\n" ); document.write( "Then the length is: 2x+5
\n" ); document.write( "Area is: 78 cm^2
\n" ); document.write( "Area=length*width
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\n" ); document.write( "78=x(2x+5)
\n" ); document.write( "78=2x^2+5x
\n" ); document.write( "0=2x^2+5x-78
\n" ); document.write( "This is in standard form:\"ax%5E2%2Bbx%2Bc=0\"
\n" ); document.write( "We can use the quadratic formula to solve it:\"highlight%28x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29%29\"
\n" ); document.write( "a=2, b=5, and c=-78
\n" ); document.write( "\"x=%28-5%2B-sqrt%285%5E2-4%282%29%28-78%29%29%29%2F%282%282%29%29\"
\n" ); document.write( "\"x=%28-5%2B-sqrt%2825%2B624%29%29%2F4\"
\n" ); document.write( "\"x=%28-5%2B-sqrt%28649%29%29%2F4\"
\n" ); document.write( "You can ignore the negative dimension.
\n" ); document.write( "x=5.119
\n" ); document.write( "The width is: x=5.119 cm
\n" ); document.write( "Length is:2x+5=2(5.119)+5=15.238 cm
\n" ); document.write( "Happy Calculating!!!
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